JEE Main 2024 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 31 January 2024, Shift 2, Physics Q43

Question 43 of 90 in this shift, Physics question 13 of 30, Section A.

An AC voltage

V=20\sin 200\pi t

is applied to a series LCR circuit which drives a current

I=10\sin\left(200\pi t+\frac{\pi}{3}\right)

. The average power dissipated is:

(1)21.6 W
(2)200 W
(3)50 WOfficial answer
(4)173.2 W

Official answer

Option 3

NTA final key.

Chapter: Alternating Current
Topic: Phasor Diagrams
Idea tested: Power Factor from Phasors

Same idea in other shifts

Asked 4× in all

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6 Sep 2020, Shift 2 · Q23In a series LR circuit, power of 400 W is dissipated from a source of 250 V, 50 Hz. The power factor of the circuit is 0.8. In order to…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.