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Saturday, 31 October

JEE Main 2022 · PhysicsMultiple choiceSingle correctMediumApplication

JEE Main 26 July 2022, Shift 1, Physics Q36

Question 36 of 90 in this shift, Physics question 6 of 30, Section A.

The magnetic field of a plane electromagnetic wave is given by : B⃗=2×10−8sin⁡(0.5×103x+1.5×1011t) j^\vec{B} = 2\times10^{-8}\sin(0.5\times10^{3}x + 1.5\times10^{11}t)\,\hat{j} T. The amplitude of the electric field would be :
  1. (1)6 Vm−16\ \mathrm{Vm^{-1}} along xx-axis
  2. (2)3 Vm−13\ \mathrm{Vm^{-1}} along zz-axis
  3. (3)6 Vm−16\ \mathrm{Vm^{-1}} along zz-axisOfficial answer
  4. (4)2×10−8 Vm−12\times10^{-8}\ \mathrm{Vm^{-1}} along zz-axis

Official answer

Option 3

NTA final key.

Chapter
Electromagnetic Waves
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.