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Friday, 9 October

JEE Main 2021 · ChemistryMultiple choiceDiagram basedEasyApplication

JEE Main 18 March 2021, Shift 1, Chemistry Q47

Question 47 of 90 in this shift, Chemistry question 17 of 30, Section A.

[figure: aniline --(NaNO2, HCl, 273 K - 278 K)--> "X" (Major Product) --(N,N-dimethylaniline)--> "Y" (Major Product)] Considering the above reaction, X and Y respectively are :

The figure, in words

Reaction scheme of aniline diazotisation then coupling with N,N-dimethylaniline; options are skeletal structures.
  1. (1)C6H5N2+Cl−\mathrm{C_6H_5N_2^+Cl^-} and C6H5−N=N−C6H4−N(CH3)2\mathrm{C_6H_5{-}N{=}N{-}C_6H_4{-}N(CH_3)_2} (azo coupling at the ortho position of dimethylaniline)
  2. (2)C6H5Cl\mathrm{C_6H_5Cl} and C6H5−N=N−C6H4−N(CH3)2\mathrm{C_6H_5{-}N{=}N{-}C_6H_4{-}N(CH_3)_2} (azo coupling at the ortho position of dimethylaniline)
  3. (3)C6H5N2+Cl−\mathrm{C_6H_5N_2^+Cl^-} and C6H5−N=N−C6H4−N(CH3)2\mathrm{C_6H_5{-}N{=}N{-}C_6H_4{-}N(CH_3)_2} (azo coupling at the para position of dimethylaniline)Official answer
  4. (4)C6H5Cl\mathrm{C_6H_5Cl} and C6H5−N=N−C6H4−N(CH3)2\mathrm{C_6H_5{-}N{=}N{-}C_6H_4{-}N(CH_3)_2} (azo coupling at the para position of dimethylaniline)

Official answer

Option 3

NTA final key.

Chapter
Amines