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JEE Main 2 April 2025, Shift 2, Chemistry Q69

Question 69 of 75 in this shift, Chemistry question 19 of 25, Section A.

When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid (273 K) and acidified with acetic acid, the mass (g) of 0.1 mole of product formed is : (Given molar mass in

\mathrm{g\,mol^{-1}}

H : 1, C : 12, N : 14, O : 16, S : 32)

(1) $330$
(2) $33$ Official answer
(3) $66$
(4) $343$

Official answer

Option 2

NTA final key.

Chapter: Amines
Topic: Diazonium Salts
Idea tested: Azo Coupling Reactions

JEE Main 2 April 2025, Shift 2, Chemistry Q69

Same idea in other shifts