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Friday, 9 October

JEE Main 2024 · ChemistryMultiple choiceDiagram basedEasyMulti-step

JEE Main 30 January 2024, Shift 2, Chemistry Q79

Question 79 of 90 in this shift, Chemistry question 19 of 30, Section A.

The products A and B formed in the following reaction scheme are respectively Benzene →ii) Sn / HCli) con. HNO3/Con. H2SO4, 323–333 K\xrightarrow[\text{ii) Sn / HCl}]{\text{i) con. }\mathrm{HNO_3}/\text{Con. }\mathrm{H_2SO_4},\ 323\text{--}333\ \mathrm{K}} A →ii) Phenoli) NaNO2, HCl, 273–278 K\xrightarrow[\text{ii) Phenol}]{\text{i) }\mathrm{NaNO_2},\ \mathrm{HCl},\ 273\text{--}278\ \mathrm{K}} B

The figure, in words

Reaction scheme: benzene, (i) conc. HNO3/conc. H2SO4 at 323-333 K, (ii) Sn/HCl gives A; then (i) NaNO2, HCl at 273-278 K, (ii) phenol gives B. Options are structure pairs (A, B).
  1. (1)[figure: A = aniline; B = 2-amino-4'-hydroxybiphenyl (biphenyl with NH2 ortho on one ring and OH para on the other ring)]
  2. (2)[figure: A = 3-chloronitrobenzene; B = 4-hydroxy-3'-nitrobiphenyl]
  3. (3)[figure: A = aniline; B = 4-hydroxyazobenzene, HO-C6H4-N=N-C6H5 (para)]Official answer
  4. (4)[figure: A = aniline; B = 2-hydroxyazobenzene, ortho-HO-C6H4-N=N-C6H5]

Official answer

Option 3

NTA final key.

Chapter
Amines

Same idea in other shifts

Asked 3× in all
  1. 2 Apr 2025, Shift 2 · Q69When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid (273 K) and acidified with acetic acid,…MediumSingle correct
  2. 31 Jan 2024, Shift 2 · Q80The azo-dye (Y) formed in the following reactions is Sulphanilic acid + NaNO2\mathrm{NaNO_2} + CH3COOH\mathrm{CH_3COOH} →\rightarrow X. X +…MediumDiagram basedHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.