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Friday, 9 October

JEE Main 2026 · ChemistryNumerical answerNumerical valueMediumMulti-step

JEE Main 6 April 2026, Shift 1, Chemistry Q72

Question 72 of 75 in this shift, Chemistry question 22 of 25, Section B.

Consider the following sequence of reactions. [C6H5−N=N−NH−C6H5\mathrm{C_6H_5-N=N-NH-C_6H_5}] →(iii) Warm 40 – 45°C(i) HCl; (ii) Aniline (in excess); (iv) Cool, acetic acid\xrightarrow[\text{(iii) Warm 40 – 45°C}]{\text{(i) HCl; (ii) Aniline (in excess); (iv) Cool, acetic acid}} Yellow Product (X) The percentage of nitrogen in the yellow product (X) formed is ________%. (Nearest Integer) (Given Molar mass in g mol−1^{-1} H:1, C:12, N:14)

The figure, in words

Reactant is diazoaminobenzene, C6H5-N=N-NH-C6H5 (two benzene rings joined by N=N-NH); reagents: (i) HCl, (ii) aniline (in excess), (iii) warm 40-45 C, (iv) cool, acetic acid; gives yellow product (X).

Official answer

21

NTA final key.

Chapter
Amines