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JEE Main 17 March 2021, Shift 2, Physics Q26

Question 26 of 90 in this shift, Physics question 26 of 30, Section B.

The electric field in a region is given by

\vec{\mathrm{E}}=\frac{2}{5}\mathrm{E_0}\hat{i}+\frac{3}{5}\mathrm{E_0}\hat{j}

with

\mathrm{E_0}=4.0\times10^{3}\frac{\mathrm{N}}{\mathrm{C}}

. The flux of this field through a rectangular surface area 0.4

\mathrm{m^2}

parallel to the Y

-

Z plane is ____________

\mathrm{Nm^2\,C^{-1}}

Official answer

640

NTA final key.

Chapter: Electric Charges and Fields
Topic: Gauss's Law
Idea tested: Electric Flux Calculation

Same idea in other shifts

Asked 6× in all

7 Apr 2025, Shift 2 · Q50The electric field in a region is given by $\vec{E}=\left(2\hat{i}+4\hat{j}+6\hat{k}\right)\times10^3$ N/C. The flux of the field through…EasyNumerical value
8 Apr 2024, Shift 1 · Q55An electric field, $\vec{E}=\frac{2\hat{i}+6\hat{j}+8\hat{k}}{\sqrt{6}}$ passes through the surface of 4 m $^2$ area having unit vector…EasyNumerical value
31 Aug 2021, Shift 2 · Q20Choose the incorrect statement : (a) The electric lines of force entering into a Gaussian surface provide negative flux. (b) A charge 'q'…EasyOther
25 Feb 2021, Shift 1 · Q26The electric field in a region is given by $\vec{E}=\left(\frac{3}{5}E_0\hat{i}+\frac{4}{5}E_0\hat{j}\right)\frac{N}{C}$ . The ratio of…EasyNumerical value
9 Jan 2020, Shift 2 · Q22An electric field $\vec{E} = 4x\,\hat{i} - (y^2+1)\,\hat{j}$ N/C passes through the box shown in figure. The flux of the electric field…MediumNumerical valueHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.