Learn

Saturday, 31 October

JEE Main 2021 · PhysicsNumerical answerNumerical valueHardCalculation

JEE Main 17 March 2021, Shift 2, Physics Q25

Question 25 of 90 in this shift, Physics question 25 of 30, Section B.

Seawater at a frequency f=9×102f=9\times10^{2} Hz, has permittivity ε=80ε0\varepsilon=80\varepsilon_0 and resistivity ρ=0.25 Ω\rho=0.25\ \Omegam. Imagine a parallel plate capacitor is immersed in seawater and is driven by an alternating voltage source V(t)=V0 sin(2πft)\mathrm{V(t)=V_0\ sin(2\pi}ft\mathrm{)}. Then the conduction current density becomes 10x10^{x} times the displacement current density after time t=1800\mathrm{t}=\frac{1}{800}s. The value of xx is ____________. (Given : 14πε0=9×109 Nm2C−2\frac{1}{4\pi\varepsilon_0}=9\times10^{9}\ \mathrm{Nm^2C^{-2}})

Official answer

6

NTA final key.