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Friday, 9 October

JEE Main 2020 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 9 January 2020, Shift 2, Physics Q22

Question 22 of 75 in this shift, Physics question 22 of 25, Section B.

An electric field E⃗=4x i^−(y2+1) j^\vec{E} = 4x\,\hat{i} - (y^2+1)\,\hat{j} N/C passes through the box shown in figure. The flux of the electric field through surfaces ABCD and BCGF are marked as ϕI\phi_I and ϕII\phi_{II} respectively. The difference between (ϕI−ϕII)(\phi_I - \phi_{II}) is (in Nm2^2/C) ______.

The figure, in words

Rectangular box in x-y-z axes with vertices A(0,0,2), B(3,0,2), C(3,2,2), D(0,2,2), E(0,0,0), F(3,0,0), G(3,2,0), H(0,2,0).

Official answer

-48.00

NTA final key (Jan 2020).

Chapter
Electric Charges and Fields
Topic
Gauss's Law
Idea tested
Electric Flux Calculation

Same idea in other shifts

Asked 3× in all
  1. 7 Apr 2025, Shift 2 · Q50The electric field in a region is given by E⃗=(2i^+4j^+6k^)×103\vec{E}=\left(2\hat{i}+4\hat{j}+6\hat{k}\right)\times10^3 N/C. The flux of the field through…EasyNumerical value
  2. 8 Apr 2024, Shift 1 · Q55An electric field, E⃗=2i^+6j^+8k^6\vec{E}=\frac{2\hat{i}+6\hat{j}+8\hat{k}}{\sqrt{6}} passes through the surface of 4 m2^2 area having unit vector…EasyNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.