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Friday, 9 October

JEE Main 2021 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 16 March 2021, Shift 2, Maths Q61

Question 61 of 90 in this shift, Maths question 1 of 30, Section A.

If the foot of the perpendicular from point (4, 3, 8) on the line L1:x−al=y−23=z−b4L_1:\frac{x-a}{l}=\frac{y-2}{3}=\frac{z-b}{4}, l≠0l\neq0 is (3, 5, 7), then the shortest distance between the line L1L_1 and line L2:x−23=y−44=z−55L_2:\frac{x-2}{3}=\frac{y-4}{4}=\frac{z-5}{5} is equal to :
  1. (1)16\frac{1}{\sqrt6}Official answer
  2. (2)12\frac{1}{2}
  3. (3)13\frac{1}{\sqrt3}
  4. (4)23\sqrt{\frac{2}{3}}

Official answer

Option 1

NTA final key.