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Friday, 9 October

JEE Main 2026 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 5 April 2026, Shift 2, Maths Q14

Question 14 of 75 in this shift, Maths question 14 of 25, Section A.

Let a triangle PQR be such that P and Q lie on the line x+38=y−42=z+12\frac{x+3}{8}=\frac{y-4}{2}=\frac{z+1}{2} and are at a distance of 6 units from R (1,2,3)(1, 2, 3). If (α,β,γ)(\alpha, \beta, \gamma) is the centroid of Δ\DeltaPQR, then α+β+γ\alpha+\beta+\gamma is equal to :
  1. (1)44
  2. (2)55
  3. (3)66Official answer
  4. (4)88

Official answer

Option 3

NTA final key.