JEE Main 2021 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 16 March 2021, Shift 2, Chemistry Q60

Question 60 of 90 in this shift, Chemistry question 30 of 30, Section B.

In Duma's method of estimation of nitrogen, 0.1840 g of an organic compound gave 30 mL of nitrogen collected at 287 K and 758 mm of Hg pressure. The percentage composition of nitrogen in the compound is ________. (Round off to the Nearest Integer). [Given : Aqueous tension at 287 K = 14 mm of Hg]

Official answer

NTA final key.

Chapter: Organic Chemistry: Some Basic Principles and Techniques
Topic: Stoichiometry
Idea tested: Stoichiometry of Dumas Method

Same idea in other shifts

Asked 6× in all

2 Apr 2025, Shift 2 · Q64In Dumas' method for estimation of nitrogen, 0.5 gram of an organic compound gave 60 mL of nitrogen collected at 300 K temperature and 715…MediumSingle correct
3 Apr 2025, Shift 1 · Q75During estimation of nitrogen by Dumas' method of compound X (0.42 g) [structure X: piperazine, six-membered ring with two NH groups at…EasyNumerical valueHas a figure
3 Apr 2025, Shift 2 · Q64In Dumas' method for estimation of nitrogen 0.4 g of an organic compound gave 60 mL of nitrogen collected at 300 K temperature and 715 mm…MediumSingle correct
7 Apr 2025, Shift 2 · Q74In Dumas' method 292 mg of an organic compound released 50 mL of nitrogen gas ( $\mathrm{N_2}$ ) at 300 K temperature and 715 mm Hg…MediumNumerical value
6 Sep 2020, Shift 2 · Q32Match the following : Test / Method — Reagent (i) Lucas Test (a) $\mathrm{C_6H_5SO_2Cl}$ / aq. KOH (ii) Dumas method (b) $\mathrm{HNO_3}$ …MediumMatch the list

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.