JEE Main 2025 · ChemistryMultiple choiceSingle correctMediumCalculation

JEE Main 3 April 2025, Shift 2, Chemistry Q64

Question 64 of 75 in this shift, Chemistry question 14 of 25, Section A.

In Dumas' method for estimation of nitrogen 0.4 g of an organic compound gave 60 mL of nitrogen collected at 300 K temperature and 715 mm Hg pressure. The percentage composition of nitrogen in the compound is (Given : Aqueous tension at 300 K = 15 mm Hg)

(1)17.46 %
(2)15.71 %Official answer
(3)20.95 %
(4)7.85 %

Official answer

Option 2

NTA final key.

Chapter: Organic Chemistry: Some Basic Principles and Techniques
Topic: Stoichiometry
Idea tested: Stoichiometry of Dumas Method

Same idea in other shifts

Asked 6× in all

2 Apr 2025, Shift 2 · Q64In Dumas' method for estimation of nitrogen, 0.5 gram of an organic compound gave 60 mL of nitrogen collected at 300 K temperature and 715…MediumSingle correct
3 Apr 2025, Shift 1 · Q75During estimation of nitrogen by Dumas' method of compound X (0.42 g) [structure X: piperazine, six-membered ring with two NH groups at…EasyNumerical valueHas a figure
7 Apr 2025, Shift 2 · Q74In Dumas' method 292 mg of an organic compound released 50 mL of nitrogen gas ( $\mathrm{N_2}$ ) at 300 K temperature and 715 mm Hg…MediumNumerical value
16 Mar 2021, Shift 2 · Q60In Duma's method of estimation of nitrogen, 0.1840 g of an organic compound gave 30 mL of nitrogen collected at 287 K and 758 mm of Hg…MediumNumerical value
6 Sep 2020, Shift 2 · Q32Match the following : Test / Method — Reagent (i) Lucas Test (a) $\mathrm{C_6H_5SO_2Cl}$ / aq. KOH (ii) Dumas method (b) $\mathrm{HNO_3}$ …MediumMatch the list

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.