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Saturday, 31 October

JEE Main 2021 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 26 August 2021, Shift 2, Physics Q16

Question 16 of 90 in this shift, Physics question 16 of 30, Section A.

A cylindrical container of volume 4.0×10−3 m34.0\times10^{-3}\ \mathrm{m^3} contains one mole of hydrogen and two moles of carbon dioxide. Assume the temperature of the mixture is 400 K. The pressure of the mixture of gases is : [Take gas constant as 8.3 J mol−1^{-1} K−1^{-1}]
  1. (1)24.9×10524.9\times10^{5} PaOfficial answer
  2. (2)24.9×10324.9\times10^{3} Pa
  3. (3)24.9 Pa
  4. (4)249×101249\times10^{1} Pa

Official answer

Option 1

NTA final key.

Chapter
Kinetic Theory
Topic
Kinetic Theory of Gases
Idea tested
Microscopic Dalton's Law

Same idea in other shifts

Asked 2× in all
  1. 26 Feb 2021, Shift 1 · Q25A container is divided into two chambers by a partition. The volume of first chamber is 4.5 litre and second chamber is 5.5 litre. The…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.