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Saturday, 31 October

JEE Main 2021 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 26 February 2021, Shift 1, Physics Q25

Question 25 of 90 in this shift, Physics question 25 of 30, Section B.

A container is divided into two chambers by a partition. The volume of first chamber is 4.5 litre and second chamber is 5.5 litre. The first chamber contain 3.0 moles of gas at pressure 2.0 atm and second chamber contain 4.0 moles of gas at pressure 3.0 atm. After the partition is removed and the mixture attains equilibrium, then, the common equilibrium pressure existing in the mixture is x×10−1x\times10^{-1} atm. Value of xx is __________.

Official answer

26

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 26 Aug 2021, Shift 2 · Q16A cylindrical container of volume 4.0×10−3 m34.0\times10^{-3}\ \mathrm{m^3} contains one mole of hydrogen and two moles of carbon dioxide. Assume…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.