JEE Main 2021 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 3 August 2021, Shift 2, Physics Q9

Question 9 of 90 in this shift, Physics question 9 of 30, Section A.

The velocity of a particle starting from origin which is set into motion at

t = 0

varies as

V = V_0(2-t)

, where

V_0

is a positive constant. Find the distance covered and displacement by the particle in 4 second.

(1) $4V_0,\ 0$ Official answer
(2) $4V_0,\ V_0$
(3) $V_0,\ 4V_0$
(4) $V_0,\ 0$

Official answer

Option 1

NTA final key.

Chapter: Motion in a Straight Line
Topic: Kinematics in 1D
Idea tested: Distance Calculation with Turning Points

Same topic in other shifts

All Kinematics in 1D questions

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.