JEE Main 2021 (3 Aug, Shift 2) Physics Q8: Projectile Motion

Question

A projectile is thrown with initial velocity of

(3\hat{i}+4\hat{j})\ \mathrm{m/s}

. Here '

\hat{i}

' is along the horizontal direction and '

\hat{j}

' is assumed in vertical direction. The equation of the trajectory is - (Take

g = 10\ \mathrm{m/s^2}

)

Official answer

Option 1

NTA final key.

Accepted Answer

Option 1: $9y = 12x - 5x^2$

Answer

$9y = 12x - 5x^2$

Answer

$9y = 4x - 5x^2$

Answer

$9y = 4x - 25x^2$

Answer

$5y = 12x - 9x^2$

JEE Main 3 August 2021, Shift 2, Physics Q8