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Friday, 9 October

JEE Main 2020 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 9 January 2020, Shift 2, Physics Q9

Question 9 of 75 in this shift, Physics question 9 of 25, Section A.

A small spherical droplet of density dd is floating exactly half immersed in a liquid of density ρ\rho and surface tension TT. The radius of the droplet is (take note that the surface tension applies an upward force on the droplet) :
  1. (1)r=T(d−ρ)gr = \sqrt{\frac{T}{(d-\rho)g}}
  2. (2)r=3T(2d−ρ)gr = \sqrt{\frac{3T}{(2d-\rho)g}}Official answer
  3. (3)r=2T3(d+ρ)gr = \sqrt{\frac{2T}{3(d+\rho)g}}
  4. (4)r=T(d+ρ)gr = \sqrt{\frac{T}{(d+\rho)g}}

Official answer

Option 2

NTA final key (Jan 2020).