JEE Main 2026 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 2 April 2026, Shift 1, Physics Q45

Question 45 of 75 in this shift, Physics question 20 of 25, Section A.

A liquid drop of diameter

2

mm breaks into

512

droplets. The change in surface energy is

\alpha\times10^{-6}

J. The value of

\alpha

is ________. (Take surface tension of liquid

=0.08

N/m)

(1) $10$
(2) $7$ Official answer
(3) $8$
(4) $11$

Official answer

Option 2

NTA final key.

Chapter: Mechanical Properties of Fluids
Topic: Surface Tension
Idea tested: Splitting and Coalescence

Same idea in other shifts

Asked 4× in all

5 Apr 2026, Shift 2 · Q33Eight mercury drops, each of radius $r$ , coalesce to form a bigger drop. The surface energy released in this process is __________. (S is…EasySingle correct
2 Apr 2025, Shift 2 · Q31Two water drops each of radius $r$ coalesce to form a bigger drop. If $T$ is the surface tension, the surface energy released in this…EasySingle correct
30 Jan 2024, Shift 2 · Q53A big drop is formed by coalescing 1000 small identical drops of water. If $E_1$ be the total surface energy of 1000 small drops of water…EasyNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.