JEE Main 2026 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 2 April 2026, Shift 1, Physics Q46

Question 46 of 75 in this shift, Physics question 21 of 25, Section B.

In single slit diffraction pattern, the wavelength of light used is

628

nm and slit width is

0.2

mm, the angular width of central maximum is

\alpha\times10^{-2}

degrees. The value of

\alpha

is __________.

Official answer

NTA final key.

Chapter: Wave Optics
Topic: Single Slit Diffraction
Idea tested: Angular Width of Central Max

Same topic in other shifts

All Single Slit Diffraction questions

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.