JEE Main 2026 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 4 April 2026, Shift 1, Physics Q47

Question 47 of 75 in this shift, Physics question 22 of 25, Section B.

The surface tension of a soap solution is

3.5\times10^{-2}

N/m. The work required to increase the radius of a soap bubble from

1

cm to

2

cm is

\alpha\times10^{-6}

J. The value of

\alpha

is ______. (

\pi=22/7

)

Official answer

264

NTA final key.

Chapter: Mechanical Properties of Fluids
Topic: Surface Tension
Idea tested: Work Done in Expanding a Soap Bubble

Same topic in other shifts

All Surface Tension questions

2 Apr 2026, Shift 1 · Q45A liquid drop of diameter $2$ mm breaks into $512$ droplets. The change in surface energy is $\alpha\times10^{-6}$ J. The value of…EasySingle correct
2 Apr 2026, Shift 2 · Q33The surface tension of a soap bubble is 0.03 N/m. The work done in increasing the diameter of bubble from 2 cm to 6 cm is…EasySingle correct
5 Apr 2026, Shift 2 · Q33Eight mercury drops, each of radius $r$ , coalesce to form a bigger drop. The surface energy released in this process is __________. (S is…EasySingle correct
2 Apr 2025, Shift 2 · Q31Two water drops each of radius $r$ coalesce to form a bigger drop. If $T$ is the surface tension, the surface energy released in this…EasySingle correct
3 Apr 2025, Shift 2 · Q47The excess pressure inside a soap bubble A in air is half the excess pressure inside another soap bubble B in air. If the volume of the…EasyNumerical value
7 Apr 2025, Shift 2 · Q32A capillary tube of radius 0.1 mm is partly dipped in water (surface tension 70 dyn/cm and glass water contact angle $\approx 0^\circ$ )…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.