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Friday, 9 October

JEE Main 2020 · ChemistryMultiple choiceOtherMediumData or graph

JEE Main 8 January 2020, Shift 1, Chemistry Q31

Question 31 of 75 in this shift, Chemistry question 6 of 25, Section A.

A graph of vapour pressure and temperature for three different liquids X, Y, and Z is shown below : The following inferences are made : (A) X has higher intermolecular interactions compared to Y. (B) X has lower intermolecular interactions compared to Y. (C) Z has lower intermolecular interactions compared to Y. The correct inference(s) is/are :

The figure, in words

Vapour pressure (mm Hg; ticks 200, 400, 500, 800) vs temperature (K; ticks 293, 313, 333, 353). Three rising curves X, Y, Z; X is leftmost/steepest (highest vapour pressure at a given T), then Y, then Z (rightmost).
  1. (1)(A)
  2. (2)(B)Official answer
  3. (3)(C)
  4. (4)(A) and (C)

Official answer

Option 2

NTA final key (Jan 2020).

Chapter
States of Matter
Topic
Colligative Properties
Idea tested
Vapor Pressure-Temperature Graph Interpretation

Same topic in other shifts

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.