JEE Main 2026 · ChemistryNumerical answerNumerical valueMediumMulti-step

JEE Main 4 April 2026, Shift 1, Chemistry Q75

Question 75 of 75 in this shift, Chemistry question 25 of 25, Section B.

A non-volatile, non-electrolyte solid solute when dissolved in

40

g of a solvent, the vapour pressure of the solvent decreased from

760

mm Hg to

750

mm Hg. If the same solution boils at

320

K, then the number of moles of the solvent present in the solution is ______. (Nearest integer) [Given: boiling point of the pure solvent

=319.5

K_b

of the solvent

=0.3\ \mathrm{K\ kg\ mol^{-1}}

]

Official answer

NTA final key.

Chapter: Solutions
Topic: Colligative Properties
Idea tested: Boiling Point Elevation

Same idea in other shifts

Asked 5× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.