JEE Main 2025 · ChemistryMultiple choiceSingle correctEasyCalculation

JEE Main 3 April 2025, Shift 1, Chemistry Q54

Question 54 of 75 in this shift, Chemistry question 4 of 25, Section A.

2 moles each of ethylene glycol and glucose are dissolved in 500 g of water. The boiling point of the resulting solution is: (Given : Ebullioscopic constant of water =

0.52\ \mathrm{K\,kg\,mol^{-1}}

)

(1)379.2 K
(2)277.3 K
(3)377.3 KOfficial answer
(4)375.3 K

Official answer

Option 3

NTA final key.

Chapter: Solutions
Topic: Colligative Properties
Idea tested: Boiling Point Elevation

Same idea in other shifts

Asked 5× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.