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Friday, 9 October

JEE Main 2026 · ChemistryMultiple choiceSingle correctEasyCalculation

JEE Main 2 April 2026, Shift 2, Chemistry Q55

Question 55 of 75 in this shift, Chemistry question 5 of 25, Section A.

Solution A is prepared by dissolving 1 g of a protein (molar mass = 50000 g mol−1^{-1}) in 0.5 L of water at 300 K. Its osmotic pressure is xx bar. Solution B is made by dissolving 2 g of same protein in 1 L of water at 300 K. Osmotic pressure of solution B is yy bar. Entire solution of A is mixed with entire solution of B at same temperature. The osmotic pressure of resultant solution is zz bar., yy and zz respectively are: (R = 0.083 L bar mol−1^{-1} K−1^{-1})
  1. (1)9.96×10−49.96 \times 10^{-4}; 9.96×10−49.96 \times 10^{-4}; 9.96×10−49.96 \times 10^{-4}Official answer
  2. (2)9.96×10−49.96 \times 10^{-4}; 9.96×10−49.96 \times 10^{-4}; 19.92×10−419.92 \times 10^{-4}
  3. (3)4.98×10−44.98 \times 10^{-4}; 4.98×10−44.98 \times 10^{-4}; 9.96×10−49.96 \times 10^{-4}
  4. (4)4.98×10−44.98 \times 10^{-4}; 4.98×10−44.98 \times 10^{-4}; 4.98×10−44.98 \times 10^{-4}

Official answer

Option 1

NTA final key.

Chapter
Solutions
Topic
Colligative Properties
Idea tested
Osmotic Pressure of Mixed Solutions

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.