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Friday, 9 October

JEE Main 2017 · PhysicsMultiple choiceSingle correctMediumApplication

JEE Main 2 April 2017 (offline), Physics Q17

Question 17 of 90 in this shift, Physics question 17 of 30.

In the above circuit the current in each resistance is :

The figure, in words

Rectangular circuit: three 2 V cells in the top wire and three 2 V cells in the bottom wire, with three 1 Ω resistors connected vertically between the top and bottom wires (two inside, one at the right end).
  1. (1)1 A
  2. (2)0.25 A
  3. (3)0.5 A
  4. (4)0 AOfficial answer

Official answer

Option 4

CBSE answer key (25/04/2017, used for result).

Chapter
Current Electricity
Topic
Kirchhoff's Laws
Idea tested
Kirchhoff's Voltage Law (KVL)

Same idea in other shifts

Asked 6× in all
  1. 5 Apr 2026, Shift 1 · Q34Refer to the figure given below. The values of I1I_1, I2I_2 and I3I_3 are ________.MediumDiagram basedHas a figure
  2. 9 Apr 2024, Shift 1 · Q56The current flowing through the 1 Ω1\ \Omega resistor is n10\frac{n}{10} A. The value of n is ________.MediumNumerical valueHas a figure
  3. 11 Apr 2023, Shift 1 · Q54In the circuit diagram shown in figure given below, the current flowing through resistance 3 Ω3\ \Omega is x3\frac{x}{3} A. The value of…MediumNumerical valueHas a figure
  4. 29 Jun 2022, Shift 1 · Q60For the network shown below, the value of VB−VAV_B - V_A is ____________ V.EasyNumerical valueHas a figure
  5. 6 Sep 2020, Shift 2 · Q13In the figure shown, the current in the 10 V battery is close to :MediumDiagram basedHas a figure

Question text from the official JEE Main paper published by NTA (CBSE ran the 2017 exam); answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.