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Friday, 9 October

JEE Main 2017 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 2 April 2017 (offline), Physics Q18

Question 18 of 90 in this shift, Physics question 18 of 30.

A magnetic needle of magnetic moment 6.7×10−2 Am26.7\times10^{-2}\ \mathrm{Am^2} and moment of inertia 7.5×10−6 kg m27.5\times10^{-6}\ \mathrm{kg\,m^2} is performing simple harmonic oscillations in a magnetic field of 0.01 T. Time taken for 10 complete oscillations is :
  1. (1)6.65 sOfficial answer
  2. (2)8.89 s
  3. (3)6.98 s
  4. (4)8.76 s

Official answer

Option 1

CBSE answer key (25/04/2017, used for result).

Chapter
Magnetism and Matter
Topic
Magnetic Dipole Moment
Idea tested
Small Oscillations of a Magnetic Dipole

Same idea in other shifts

Asked 2× in all
  1. 9 Jan 2020, Shift 2 · Q13A small circular loop of conducting wire has radius aa and carries current II. It is placed in a uniform magnetic field BB…MediumSingle correct

Question text from the official JEE Main paper published by NTA (CBSE ran the 2017 exam); answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.