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Friday, 9 October

JEE Main 2017 · PhysicsMultiple choiceSingle correctEasyApplication

JEE Main 2 April 2017 (offline), Physics Q16

Question 16 of 90 in this shift, Physics question 16 of 30.

In the given circuit diagram when the current reaches steady state in the circuit, the charge on the capacitor of capacitance C will be :

The figure, in words

Circuit: top branch has battery E in series with resistor r; middle branch has capacitor C in series with resistor r1; bottom branch has resistor r2; all three branches connected in parallel between the same two nodes.
  1. (1)CECE
  2. (2)CEr1(r2+r)CE\frac{r_1}{(r_2+r)}
  3. (3)CEr2(r+r2)CE\frac{r_2}{(r+r_2)}Official answer
  4. (4)CEr1(r1+r)CE\frac{r_1}{(r_1+r)}

Official answer

Option 3

CBSE answer key (25/04/2017, used for result).

Chapter
Current Electricity
Topic
RC Circuits
Idea tested
Initial and Steady State Behavior

Same idea in other shifts

Asked 2× in all
  1. 5 Apr 2026, Shift 2 · Q37Under steady state condition the potential difference across the capacitor in the circuit is __________ V.MediumSingle correctHas a figure

Question text from the official JEE Main paper published by NTA (CBSE ran the 2017 exam); answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.