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Friday, 9 October

JEE Main 2017 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 2 April 2017 (offline), Physics Q15

Question 15 of 90 in this shift, Physics question 15 of 30.

A capacitance of 2 μF2\ \mu\mathrm{F} is required in an electrical circuit across a potential difference of 1.0 kV. A large number of 1 μF1\ \mu\mathrm{F} capacitors are available which can withstand a potential difference of not more than 300 V. The minimum number of capacitors required to achieve this is :
  1. (1)2
  2. (2)16
  3. (3)24
  4. (4)32Official answer

Official answer

Option 4

CBSE answer key (25/04/2017, used for result).