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Friday, 9 October

NEET UG 2023 · Physics · Question 38

NEET 2023 Physics, question 38

Question 38 of the NEET 2023 paper (code G6) is a Physics question from Alternating Current. Its idea, Series LCR Impedance Calculation, was asked twice, in 2023 and 2026, across NEET 2017–2026. The NTA final answer key gives option 4.

Updated 2026-10-08

Q38 · Physics

The net impedance of circuit (as shown in figure) will be :

The figure, described in words

Series LCR circuit: L = (50/π) mH, C = (10^3/π) μF, R = 10 Ω, across a 220 V, 50 Hz ac source.

  1. 125 Ω\Omega
  2. 2102 Ω10\sqrt{2}\ \Omega
  3. 315 Ω\Omega
  4. 455 Ω5\sqrt{5}\ \OmegaOfficial answer

Official answer: option 4 · NTA final answer key

Same idea

Series LCR Impedance Calculation, in other papers

NEET asked this idea twice, in 2023 and 2026. The other question below.

  • 2026 Q30An ac voltage V=220sin⁡(2×103t)V=220\sin(2\times10^3t) Volt is applied to a series LCR circuit. Then the current amplitude in this circuit is : (Given :…Numerical · Easy

Series LCR Impedance Calculation: every question and how it was framed

The chapter

Alternating Current in ten years of NEET

15 questions from 2017–2026, asked in 8 of 10 papers, about 1.4 a paper. LCR Circuits alone had 15.

Alternating Current: questions per paper

0240’171’180’192’203’212’223’232’241’251’26