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Friday, 9 October

NEET UG 2022 · Chemistry · Question 91

NEET 2022 Chemistry, question 91

Question 91 of the NEET 2022 paper (code R1) is a Chemistry question from Hydrocarbons. Its idea, Reverse Ozonolysis (Parent Alkene Identification), was asked twice, in 2019 and 2022, across NEET 2017–2026. The NTA final answer key gives option 2.

Updated 2026-10-08

Q91 · Chemistry

Compound X on reaction with O3\mathrm{O_3} followed by Zn/H2O\mathrm{H_2O} gives formaldehyde and 2-methyl propanal as products. The compound X is :

  1. 1Pent-2-ene
  2. 23-Methylbut-1-eneOfficial answer
  3. 32-Methylbut-1-ene
  4. 42-Methylbut-2-ene

Official answer: option 2 · NTA final answer key

Same idea

Reverse Ozonolysis (Parent Alkene Identification), in other papers

NEET asked this idea twice, in 2019 and 2022. The other question below.

  • 2019 Q74An alkene "A" on reaction with O3O_3 and Zn−H2OZn-H_2O gives propanone and ethanal in equimolar ratio. Addition of HCl to alkene "A" gives "B"…One-line MCQ · Medium

Reverse Ozonolysis (Parent Alkene Identification): every question and how it was framed

The chapter

Hydrocarbons in ten years of NEET

25 questions from 2017–2026, asked in 10 of 10 papers, about 2.4 a paper. Hydrocarbons (Alkenes) alone had 12.

Hydrocarbons: questions per paper

0363’171’182’192’204’212’222’231’245’253’26