NEET UG 2022 · Botany · Question 121
NEET 2022 Botany, question 121
Question 121 of the NEET 2022 paper (code R1) is a Botany question from Photosynthesis in Higher Plants. Its idea, PEP Carboxylase Role, was asked only this once in NEET 2017–2026. The NTA final answer key gives option 2.
Updated 2026-10-08
Q121 · Botany
Given below are two statements :
Statement I :
The primary acceptor in plants is phosphoenolpyruvate and is found in the mesophyll cells.
Statement II :
Mesophyll cells of plants lack RuBisCo enzyme.
In the light of the above statements, choose the correct answer from the options given below :
- 1Statement I is incorrect but Statement II is correct
- 2Both Statement I and Statement II are correctOfficial answer
- 3Both Statement I and Statement II are incorrect
- 4Statement I is correct but Statement II is incorrect
Official answer: option 2 · NTA final answer key
Same idea
The only question on PEP Carboxylase Role
No other NEET paper from 2017–2026 tested this exact idea.
The chapter
Photosynthesis in Higher Plants in ten years of NEET
23 questions from 2017–2026, asked in 9 of 10 papers, about 2.2 a paper. Calvin and Hatch-Slack Cycles alone had 14.