A uniform rod of length 200 cm and mass 500 g is balanced on a wedge placed at 40 cm mark. A mass of 2 kg is suspended from the rod at 20 cm and another unknown mass 'm' is suspended from the rod at 160 cm mark as shown in the figure. Find the value of 'm' such that the rod is in equilibrium. (g = 10 m/s^2)

NEET UG 2021 · Physics · Question 43

NEET 2021 Physics, question 43

Question 43 of the NEET 2021 paper (code O1) is a Physics question from System of Particles and Rotational Motion. Its idea, Rotational Equilibrium, was asked twice, in 2021 and 2025, across NEET 2017–2026. The NTA final answer key gives option 2.

Updated 2026-10-08

Q43 · Physics

s^{2}

The figure, described in words

Stem: figure of a rod balanced on a wedge with scale marks 0, 20 cm, 40 cm, 160 cm, a 2 kg mass at 20 cm and unknown mass m at 160 cm.

\frac{1}{6}

Official answer: option 2 · NTA final answer key

Same idea

Rotational Equilibrium, in other papers

NEET asked this idea twice, in 2021 and 2025. The other question below.

2025 Q 22 A uniform rod of mass 20 kg and length 5 m leans against a smooth vertical wall making an angle of 60° with it. The other end rests on a\dots Numerical \cdot Medium

Rotational Equilibrium: every question and how it was framed

The chapter

System of Particles and Rotational Motion in ten years of NEET

25 questions from 2017–2026, asked in 10 of 10 papers, about 2.4 a paper. Rotational Motion alone had 21.

Chapter analysis Study this chapter Practise this chapter

Rotational Equilibrium, in other papers

System of Particles and Rotational Motion in ten years of NEET

System of Particles and Rotational Motion: questions per paper