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Friday, 9 October

NEET UG 2019 · Physics · Question 22

NEET 2019 Physics, question 22

Question 22 of the NEET 2019 paper (code P1) is a Physics question from Work, Energy and Power. Its idea, Work by Variable Force, was asked twice, in 2019 and 2026, across NEET 2017–2026. The NTA final answer key gives option 3.

Updated 2026-10-08

Q22 · Physics

A force F=20+10yF = 20 + 10y acts on a particle in y-direction where F is in newton and y in meter. Work done by this force to move the particle from y=0y = 0 to y=1y = 1 m is :

  1. 130 J
  2. 25 J
  3. 325 JOfficial answer
  4. 420 J

Official answer: option 3 · NTA final answer key

Same idea

Work by Variable Force, in other papers

NEET asked this idea twice, in 2019 and 2026. The other question below.

  • 2026 Q1A particle of mass M moves along a horizontal x axis from x=0x=0 to x=Lx=L. The coefficient of kinetic friction varies as a function of x as…Numerical · Medium

Work by Variable Force: every question and how it was framed

The chapter

Work, Energy and Power in ten years of NEET

16 questions from 2017–2026, asked in 9 of 10 papers, about 1.5 a paper. Work-Energy Theorem alone had 12.

Work, Energy and Power: questions per paper

0241’172’182’190’202’212’221’232’242’252’26