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Friday, 9 October

NEET UG 2018 · Chemistry · Question 77

NEET 2018 Chemistry, question 77

Question 77 of the NEET 2018 paper (code AA) is a Chemistry question from Equilibrium. Its idea, Solubility Product from Solubility, was asked twice, in 2017 and 2018, across NEET 2017–2026. The CBSE official answer key gives option 3.

Updated 2026-10-08

Q77 · Chemistry

The solubility of BaSO4\mathrm{BaSO_4} in water is 2.42×10−32.42\times10^{-3} gL−1^{-1} at 298 K. The value of its solubility product (KspK_{sp}) will be

(Given molar mass of BaSO4\mathrm{BaSO_4} = 233 g mol−1^{-1})

  1. 11.08×10−141.08\times10^{-14} mol2^2 L−2^{-2}
  2. 21.08×10−121.08\times10^{-12} mol2^2 L−2^{-2}
  3. 31.08×10−101.08\times10^{-10} mol2^2 L−2^{-2}Official answer
  4. 41.08×10−81.08\times10^{-8} mol2^2 L−2^{-2}

Official answer: option 3 · CBSE official answer key

Same idea

Solubility Product from Solubility, in other papers

NEET asked this idea twice, in 2017 and 2018. The other question below.

  • 2017 Q51Concentration of the Ag+\mathrm{Ag^+} ions in a saturated solution of Ag2C2O4\mathrm{Ag_2C_2O_4} is 2.2×10−42.2\times10^{-4} mol L−1\mathrm{L^{-1}}.…Numerical · Easy

Solubility Product from Solubility: every question and how it was framed

The chapter

Equilibrium in ten years of NEET

26 questions from 2017–2026, asked in 10 of 10 papers, about 2.5 a paper. pH and Buffer Solutions alone had 13.

Chapter analysisStudy this chapterPractise this chapter

Equilibrium: questions per paper

0363’173’183’192’201’212’222’235’244’251’26