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Friday, 9 October

NEET UG 2018 · Chemistry · Question 61

NEET 2018 Chemistry, question 61

Question 61 of the NEET 2018 paper (code AA) is a Chemistry question from Haloalkanes and Haloarenes. Its idea, Side-Chain Halogenation of Toluene, was asked only this once in NEET 2017–2026. The CBSE official answer key gives option 3.

Updated 2026-10-08

Q61 · Chemistry

The compound C7H8\mathrm{C_7H_8} undergoes the following reactions :

C7H8→3 Cl2/ΔA→Br2/FeB→Zn/HClC\mathrm{C_7H_8} \xrightarrow{3\,\mathrm{Cl_2}/\Delta} \mathrm{A} \xrightarrow{\mathrm{Br_2/Fe}} \mathrm{B} \xrightarrow{\mathrm{Zn/HCl}} \mathrm{C}

The product 'C' is

  1. 13-bromo-2,4,6-trichlorotoluene
  2. 2o-bromotoluene
  3. 3m-bromotolueneOfficial answer
  4. 4p-bromotoluene

Official answer: option 3 · CBSE official answer key

Same idea

The only question on Side-Chain Halogenation of Toluene

No other NEET paper from 2017–2026 tested this exact idea.

Side-Chain Halogenation of Toluene: every question and how it was framed

The chapter

Haloalkanes and Haloarenes in ten years of NEET

16 questions from 2017–2026, asked in 10 of 10 papers, about 1.5 a paper. Nucleophilic Substitution alone had 16.

Chapter analysisStudy this chapterPractise this chapter

Haloalkanes and Haloarenes: questions per paper

0241’171’181’191’202’212’223’233’241’251’26