Learn

Friday, 9 October

NEET UG 2018 · Physics · Question 44

NEET 2018 Physics, question 44

Question 44 of the NEET 2018 paper (code AA) is a Physics question from Mechanical Properties of Solids. Its idea, Young's Modulus Calculation, was asked twice, in 2018 and 2020, across NEET 2017–2026. The CBSE official answer key gives option 3.

Updated 2026-10-08

Q44 · Physics

Two wires are made of the same material and have the same volume. The first wire has cross-sectional area A and the second wire has cross-sectional area 3A. If the length of the first wire is increased by Δl\Delta l on applying a force F, how much force is needed to stretch the second wire by the same amount ?

  1. 14 F
  2. 26 F
  3. 39 FOfficial answer
  4. 4F

Official answer: option 3 · CBSE official answer key

Same idea

Young's Modulus Calculation, in other papers

NEET asked this idea twice, in 2018 and 2020. The other question below.

  • 2020 Q161A wire of length L, area of cross section A is hanging from a fixed support. The length of the wire changes to L1L_1 when mass M is…One-line MCQ · Easy

Young's Modulus Calculation: every question and how it was framed

The chapter

Mechanical Properties of Solids in ten years of NEET

7 questions from 2017–2026, asked in 7 of 10 papers, about 0.7 a paper. Elasticity alone had 7.

Mechanical Properties of Solids: questions per paper

0241’171’181’191’200’211’221’231’240’250’26