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Friday, 9 October

NEET UG 2017 · Chemistry · Question 77

NEET 2017 Chemistry, question 77

Question 77 of the NEET 2017 paper (code A) is a Chemistry question from Thermodynamics. Its idea, Temperature of Spontaneity, was asked only this once in NEET 2017–2026. The CBSE official answer key gives option 2.

Updated 2026-10-08

Q77 · Chemistry

For a given reaction, ΔH\Delta H = 35.5 kJ mol−1\mathrm{mol^{-1}} and ΔS\Delta S = 83.6 JK−1\mathrm{K^{-1}} mol−1\mathrm{mol^{-1}}. The reaction is spontaneous at : (Assume that ΔH\Delta H and ΔS\Delta S do not vary with temperature)

  1. 1T < 425 K
  2. 2T > 425 KOfficial answer
  3. 3all temperatures
  4. 4T > 298 K

Official answer: option 2 · CBSE official answer key

Same idea

The only question on Temperature of Spontaneity

No other NEET paper from 2017–2026 tested this exact idea.

Temperature of Spontaneity: every question and how it was framed

The chapter

Thermodynamics in ten years of NEET

32 questions from 2017–2026, asked in 10 of 10 papers, about 3.1 a paper. Gibbs Free Energy alone had 7.

Chapter analysisStudy this chapterPractise this chapter

Thermodynamics: questions per paper

0364’174’183’193’202’212’222’234’243’255’26