NEET 2017 Chemistry, question 63.

In the electrochemical cell :

Zn|$\mathrm{ZnSO_4}$ (0.01 M)||$\mathrm{CuSO_4}$ (1.0 M)|Cu, the emf of this Daniel cell is $E_1$. When the concentration of $\mathrm{ZnSO_4}$ is changed to 1.0 M and that of $\mathrm{CuSO_4}$ changed to 0.01 M, the emf changes to $E_2$. From the followings, which one is the relationship between $E_1$ and $E_2$ ? (Given, $\frac{RT}{F}$ = 0.059)