It is because of inability of ns^2 electrons of the valence shell to participate in bonding that

Sn^2+ is reducing while Pb^4+ is oxidising

Sn^2+ is oxidising while Pb^4+ is reducing

Sn^2+ and Pb^2+ are both oxidising and reducing

Sn^4+ is reducing while Pb^4+ is oxidising

NEET UG 2017 · Chemistry · Question 56

NEET 2017 Chemistry, question 56

Question 56 of the NEET 2017 paper (code A) is a Chemistry question from The p-Block Elements (Class 11). Its idea, Redox Behavior of Tin and Lead, was asked only this once in NEET 2017–2026. The CBSE official answer key gives option 1.

Updated 2026-10-08

Q56 · Chemistry

ns^2

\mathrm{Sn^{2+}}

Official answer: option 1 · CBSE official answer key

Same idea

The only question on Redox Behavior of Tin and Lead

No other NEET paper from 2017–2026 tested this exact idea.

Redox Behavior of Tin and Lead: every question and how it was framed

The chapter

The p-Block Elements (Class 11) in ten years of NEET

13 questions from 2017–2026, asked in 7 of 10 papers, about 1.3 a paper. p-Block (Group 13-14) alone had 12.

Chapter analysis

The only question on Redox Behavior of Tin and Lead

The p-Block Elements (Class 11) in ten years of NEET

The p-Block Elements (Class 11): questions per paper