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Friday, 9 October

NEET UG 2017 · Physics · Question 27

NEET 2017 Physics, question 27

Question 27 of the NEET 2017 paper (code A) is a Physics question from Thermodynamics. Its idea, Refrigerator COP Definition, was asked only this once in NEET 2017–2026. The CBSE official answer key gives option 2.

Updated 2026-10-08

Q27 · Physics

A carnot engine having an efficiency of 110\frac{1}{10} as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is :

  1. 11 J
  2. 290 JOfficial answer
  3. 399 J
  4. 4100 J

Official answer: option 2 · CBSE official answer key

Same idea

The only question on Refrigerator COP Definition

No other NEET paper from 2017–2026 tested this exact idea.

Refrigerator COP Definition: every question and how it was framed

The chapter

Thermodynamics in ten years of NEET

32 questions from 2017–2026, asked in 10 of 10 papers, about 3.1 a paper. Carnot Engine alone had 3.

Thermodynamics: questions per paper

0364’174’183’193’202’212’222’234’243’255’26