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Friday, 9 October

JEE Main Physics · Electrostatic Potential and Capacitance

Field-Potential Relation

Field-Potential Relation (Electrostatic Potential and Capacitance) was asked 2 times in 2 JEE Main shifts, 2021–2026, out of the 42 shifts Lumi analysed. 1 of the 2 had a numerical answer.

Times asked
2
in 2 shifts
Years
2021–2026
Usual format
Numerical value
Calculation
Pattern
Occasional
repeats across shifts

How it is asked

  • Field vector from potential function
  • Field from potential function

Difficulty

Easy 2Medium 0Hard 0

Where it sits

Chapter: Electrostatic Potential and Capacitance. Topic: Electric Potential, 12 questions over 9 ideas.

Other repeat ideas in this topic

Every time it came

All 2 questions

Newest first, each with its options and official answer.

  1. 6 Apr 2026, Shift 2 · Q37The electric potential as a function of x,yx, y is given by V=5(x2−y2)V=5(x^2-y^2) V. The electric field at a point (2, 3) m is __________ V/m.EasySingle correct
  2. 3 Aug 2021, Shift 2 · Q29The electric potential at point (x,0,0)(x, 0, 0) is V=(1000x+1500x2+500x3)V = \left(\frac{1000}{x}+\frac{1500}{x^2}+\frac{500}{x^3}\right) volt. The electric field…EasyNumerical value