JEE Main 2021 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 4 August 2021, Shift 2, Physics Q9

Question 9 of 90 in this shift, Physics question 9 of 30, Section A.

The electric potential at any point P(x, y, z) is

V=x^3z-x^2y-3

volts. The electric field

\vec{E}_Q

at point Q(2, 3, 1) will be (in V/m) -

(1) $8\hat{i}-12\hat{j}-3\hat{k}$
(2) $4(2\hat{i}-3\hat{j})$
(3) $4(\hat{j}-2\hat{k})$ Official answer
(4) $2(2\hat{k}-3\hat{i})$

Official answer

Option 3

NTA final key.

Chapter: Electrostatic Potential and Capacitance
Topic: Electric Potential
Idea tested: Field-Potential Relation

Same idea in other shifts

Asked 3× in all

6 Apr 2026, Shift 2 · Q37The electric potential as a function of $x, y$ is given by $V=5(x^2-y^2)$ V. The electric field at a point (2, 3) m is __________ V/m.EasySingle correct
3 Aug 2021, Shift 2 · Q29The electric potential at point $(x, 0, 0)$ is $V = \left(\frac{1000}{x}+\frac{1500}{x^2}+\frac{500}{x^3}\right)$ volt. The electric field…EasyNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.