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Friday, 9 October

JEE Main 2026 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 8 April 2026, Shift 2, Physics Q39

Question 39 of 75 in this shift, Physics question 14 of 25, Section A.

A current carrying circular loop of radius 2 cm with unit normal n^=k^+i^2\hat{n} = \frac{\hat{k} + \hat{i}}{\sqrt{2}} is placed in a magnetic field, B⃗=B0(3i^+2k^)\vec{B} = B_0\left(3\hat{i} + 2\hat{k}\right). If B0=4×10−3B_0 = 4 \times 10^{-3} T and current I=1002I = 100\sqrt{2} A, the torque experienced by the loop is ________ Wb.A. (π=3.14\pi = 3.14)
  1. (1)16×10−5 k^16 \times 10^{-5}\,\hat{k}
  2. (2)5024×10−7 k^5024 \times 10^{-7}\,\hat{k}
  3. (3)5024×10−7 i^5024 \times 10^{-7}\,\hat{i}
  4. (4)5024×10−7 j^5024 \times 10^{-7}\,\hat{j}Official answer

Official answer

Option 4

NTA final key.

Chapter
Moving Charges and Magnetism
Topic
Magnetic Dipole Moment
Idea tested
Torque on a dipole in uniform field

Same idea in other shifts

Asked 3× in all
  1. 4 Apr 2026, Shift 2 · Q49A circular coil of radius 2 cm and 125 turns carries a current of 1 A. The coil is placed in a uniform magnetic field of magnitude 0.4 T.…EasyNumerical value
  2. 31 Jan 2024, Shift 2 · Q42A uniform magnetic field of 2×10−32\times10^{-3} T acts along positive YY-direction. A rectangular loop of sides 20 cm and 10 cm with current…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.