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Friday, 9 October

JEE Main 2026 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 4 April 2026, Shift 2, Physics Q49

Question 49 of 75 in this shift, Physics question 24 of 25, Section B.

A circular coil of radius 2 cm and 125 turns carries a current of 1 A. The coil is placed in a uniform magnetic field of magnitude 0.4 T. The axis of the coil makes an angle of 30∘30^\circ with the direction of the magnetic field. The torque acting on the coil is α×10−4\alpha\times10^{-4} N.m. The value of α\alpha is ________. (π=3.14\pi=3.14)

Official answer

314

NTA final key.

Chapter
Moving Charges and Magnetism
Topic
Magnetic Dipole Moment
Idea tested
Torque on a dipole in uniform field

Same idea in other shifts

Asked 3× in all
  1. 8 Apr 2026, Shift 2 · Q39A current carrying circular loop of radius 2 cm with unit normal n^=k^+i^2\hat{n} = \frac{\hat{k} + \hat{i}}{\sqrt{2}} is placed in a magnetic…MediumSingle correct
  2. 31 Jan 2024, Shift 2 · Q42A uniform magnetic field of 2×10−32\times10^{-3} T acts along positive YY-direction. A rectangular loop of sides 20 cm and 10 cm with current…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.