JEE Main 2026 · ChemistryNumerical answerNumerical valueMediumMulti-step

JEE Main 6 April 2026, Shift 2, Chemistry Q73

Question 73 of 75 in this shift, Chemistry question 23 of 25, Section B.

500 mL of 0.2 M

\mathrm{MnO_4^-}

solution in basic medium when mixed with 500 mL of 1.5 M KI solution, oxidises iodide ions to liberate molecular iodine. This liberated iodine is then titrated with a standard

x

M thiosulphate solution in presence of starch till the end point. If 300 mL of thiosulphate was consumed, then the value of

x

is __________.

Official answer

NTA final key.

Chapter: Redox Reactions
Topic: Redox Reactions
Idea tested: Iodometric Titration Reactions

Same topic in other shifts

All Redox Reactions questions

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8 Apr 2024, Shift 1 · Q64Thiosulphate reacts differently with iodine and bromine in the reactions given below:…MediumSingle correct
9 Apr 2024, Shift 1 · Q65Given below are two statements : Statement (I) : The oxidation state of an element in a particular compound is the charge acquired by its…MediumTwo statements
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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.