/

Learn

Friday, 9 October

/

JEE Main 2026 · ChemistryNumerical answerNumerical valueMediumMulti-step

JEE Main 6 April 2026, Shift 2, Chemistry Q72

Question 72 of 75 in this shift, Chemistry question 22 of 25, Section B.

An alkane (Y) requires 8 moles of oxygen for complete combustion and on chlorination with

\mathrm{Cl_2}/h\nu

, (Y) gives only one monochlorinated product (Z). The total number of primary carbon atoms in (Y) is __________.

Official answer

4

NTA final key.

Chapter: Hydrocarbons
Topic: Alkanes and Free Radicals
Idea tested: General Stoichiometry of Alkane Combustion

Same idea in other shifts

Asked 2× in all

2 Apr 2026, Shift 1 · Q73One mole of an alkane (x) requires $8$ mole oxygen for complete combustion. Sum of number of carbon and hydrogen atoms in the alkane (x)…EasyNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.