JEE Main 2026 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 6 April 2026, Shift 1, Maths Q2

Question 2 of 75 in this shift, Maths question 2 of 25, Section A.

Let one root of the quadratic equation in

x

(k^2-15k+27)x^2+9(k-1)x+18=0

be twice the other. Then the length of the latus rectum of the parabola

y^2=6kx

is equal to:

(1)4
(2)6
(3)8
(4)12Official answer

Official answer

Option 4

NTA final key.

Chapter: Conic Sections
Topic: Quadratic Roots
Idea tested: Roots in a Specific Ratio

Same topic in other shifts

All Quadratic Roots questions

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4 Apr 2026, Shift 2 · Q2Let $S=\{z\in\mathbb{C}:z^2+4z+16=0\}$ . Then $\sum_{z\in S}|z+\sqrt{3}\,i|^2$ is equal to:EasySingle correct
4 Apr 2026, Shift 2 · Q4If $\alpha=1$ and $\beta=1+i\sqrt{2}$ , where $i=\sqrt{-1}$ are two roots of the equation $x^3+ax^2+bx+c=0$ , $a,b,c\in\mathbb{R}$ , then…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.