JEE Main 2026 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 4 April 2026, Shift 2, Maths Q4

Question 4 of 75 in this shift, Maths question 4 of 25, Section A.

\alpha=1

and

\beta=1+i\sqrt{2}

, where

i=\sqrt{-1}

are two roots of the equation

x^3+ax^2+bx+c=0

a,b,c\in\mathbb{R}

, then

\int_{-1}^{1}\left(x^3+ax^2+bx+c\right)dx

is equal to:

(1) $-2$
(2) $-4$
(3) $-8$ Official answer
(4) $-10$

Official answer

Option 3

NTA final key.

Chapter: Integrals
Topic: Quadratic Roots
Idea tested: Complex Conjugate Roots

Same idea in other shifts

Asked 4× in all

4 Apr 2026, Shift 2 · Q2Let $S=\{z\in\mathbb{C}:z^2+4z+16=0\}$ . Then $\sum_{z\in S}|z+\sqrt{3}\,i|^2$ is equal to:EasySingle correct
31 Jan 2024, Shift 1 · Q7Let $a$ be the sum of all coefficients in the expansion of $(1-2x+2x^2)^{2023}(3-4x^2+2x^3)^{2024}$ and…HardSingle correct
8 Jan 2020, Shift 1 · Q52If the equation, $x^2+bx+45=0$ ( $b\in R$ ) has conjugate complex roots and they satisfy $|z+1|=2\sqrt{10}$ , then :MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.