JEE Main 2026 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 6 April 2026, Shift 1, Maths Q17

Question 17 of 75 in this shift, Maths question 17 of 25, Section A.

The value of

\lim_{x\to 0}\left(\frac{x^2\sin^2 x}{x^2-\sin^2 x}\right)

is:

(1)2
(2)3Official answer
(3)4
(4)6

Official answer

Option 2

NTA final key.

Chapter: Limits and Derivatives
Topic: L'Hopital's Rule
Idea tested: Choosing Series Expansion over L'Hopital

Same idea in other shifts

Asked 6× in all

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31 Jan 2024, Shift 2 · Q25If $\lim_{x\to0}\frac{ax^2e^x-b\log_e(1+x)+cxe^{-x}}{x^2\sin x}=1$ , then $16(a^2+b^2+c^2)$ is equal to ________.HardNumerical value
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18 Mar 2021, Shift 1 · Q72If $\lim_{x\to0}\dfrac{\sin^{-1}x-\tan^{-1}x}{3x^3}$ is equal to L, then the value of $(6L+1)$ is :MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.